Question

Solve
$\frac{d}{dx}(3x^a+5)$

Answer 1

$\frac{d}{dx}(3x^a+5)$

$=\frac{d}{dx}\left(3x^a\right)+\frac{d}{dx}\left(5\right)$

$=3\frac{d}{dx}\left(x^a\right)+0$ since $\frac{d}{dx}\left(kx\right)=k$ and Differential of a constant $=0$

$=3a{x}^{a-1}$ using $\frac{d}{dx}\left(x^n\right)=n{x}^{n-1}$