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Question

Solve
dydx=x2y+y

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Solution

dydx=x2y+y
dydx=(x2+1)y
dyy=(x2+1)dx
Integrating on both sides we get
logy=x33+x+c
3logy=x3+3x+3c
logy3=x3+3x+c1
where c1=3c.

1190067_1330161_ans_12aa19c2f0d84d22be1028cf012ae6a9.JPG

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