Question

$solve\frac{\left(2x+3\right){\left(4-3x\right)}^3\left(x-4\right)}{{\left(x-2\right)}^2{x}^3}⩽0$

Answer 1

Solution :- given

$\Rightarrow \frac{(2x+3)(4-3x{)}^3(x-4)}{(x-2{)}^2{x}^2}⩽0$

$\Rightarrow (2x+3)(4-3x{)}^3(x-4)⩽0$

$\Rightarrow 2x+3⩽0$ or $(4-3x{)}^3⩽0$ or $x-4⩽0$

$\Rightarrow x⩽\frac{-3}{2}$ or $x⩽\frac{3}{4}$ or $x⩽4$

$\Rightarrow \frac{-3}{2}⩽x⩽\frac{3}{4}$ or $x⩽4$ Ans