Solve 6-7 - 10 - 11 6 - 1024 7-4 - 1022 3-84 - 1082

( 6.7 ×10^ 11)( 6 #10;×10^24)( 7.4 ×10^22) #10;( 3.84 ×10^8)^2 #10; #10; 6.7 × 6 × 7.43.84 × 3.84 #10;×10^ 11 + 24 + 22 16 #10; # ...

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Byju's Answer

Standard VI

Mathematics

Addition of Fractions

Solve 6.7 ×...

Question

Solve
$\frac{(6.7 \times 10^{- 11}) (6 \times 10^{24}) (7.4 \times 10^{22})}{{(3.84 \times 10^{8})}^{2}}$

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Solution

$\frac{(6.7 \times 10^{- 11}) (6 \times 10^{24}) (7.4 \times 10^{22})}{{(3.84 \times 10^{8})}^{2}}$
[Using, $a^{m} \div a^{n} = a^{(m - n)}$ & $(a^{m})^{n} = a^{m \times n}$ ]
$= \frac{6.7 \times 6 \times 7.4}{3.84 \times 3.84} \times 10^{(- 11 + 24 + 22 - 16)}$
$= \frac{6.7 \times 6 \times 7.4}{3.84 \times 3.84} \times 10^{19}$
$= \frac{297.48}{3.84 \times 3.84} \times 10^{19}$
$= \frac{297.48}{14.7456} \times 10^{19}$
$= 20.174 \times 10^{19}$

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\frac{(6.7 \times 10^{- 11}) (6 \times 10^{24}) (7.4 \times 10^{22})}{{(3.84 \times 10^{8})}^{2}}

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The mass of the earth is $6 \times 10^{24}$ kg and that of the moon is $7.4 \times 10^{22}$ kg. If distance between the earth and the moon be $3.84 \times 10^{5}$ km, calculate the force exerted by the earth on the moon. $(G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2})$ .

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Solve (6.7×10−11)(6×1024)(7.4×1022)(3.84×108)2

(6.7×10−11)(6×1024)(7.4×1022)(3.84×108)2[Using, am÷an=a(m−n) & (am)n=am×n]=6.7×6×7.43.84×3.84×10(−11+24+22−16) =6.7×6×7.43.84×3.84×1019=297.483.84×3.84×1019=297.4814.7456×1019=20.174×1019

Solve
$\frac{(6.7 \times 10^{- 11}) (6 \times 10^{24}) (7.4 \times 10^{22})}{{(3.84 \times 10^{8})}^{2}}$