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Exponents with Like Bases

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Question

Solve: $\frac{{(\frac{7}{12})}^{8}}{{(\frac{14}{6})}^{8}}$ .

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Solution

Now,
$\frac{{(\frac{7}{12})}^{8}}{{(\frac{14}{6})}^{8}}$
$= \frac{{(\frac{7}{12})}^{8}}{{(\frac{7}{3})}^{8}}$
$= {(\frac{3}{12})}^{8}$
$= {(\frac{1}{4})}^{8}$

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