Question

Solve: $\frac{\left|x\right|-1}{\left|x\right|-3}\ge 0,x\in R,x\ne \pm 3.$

Answer 1

$\frac{|x|-1}{|x|-3}\ge 0$

$|x|-1\ge 0$

$|x|\ge 1$

$x\ge 1andx\le -1$

The solution is $x\in R-\left\{\right(-1,1),\pm 3\}$