Question

Solve: $\frac{{\sin }^2{60}^o+{\tan }^2{45}^o}{{\cos }^2{17}^o+{\cos }^2{73}^o}$.

Answer 1

Now,

$\frac{{\sin }^2{60}^o+{\tan }^2{45}^o}{{\cos }^2{17}^o+{\cos }^2{73}^o}$

$=\frac{{\sin }^2{60}^o+{\tan }^2{45}^o}{{\sin }^2{73}^o+{\cos }^2{73}^o}$ [ Since $\sin {73}^o=\cos {17}^o$]

$={\sin }^2{60}^o+{\tan }^2{45}^o$

$=\frac{3}{2}+1$

$=\frac{5}{2}$.