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Question

Solve: sin3θ+cos3θcosθsinθ

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Solution

=sin30+cos30cosθsinθ=3sinθ4sin3θ+4cos3θ3cosθcosθsinθ
=4(cos3θsin3θ)+3(sinθcosθ)cosθsinθ
=4(cosθsinθ)(cos2θ+cosθsinθ+sin2θ)3(cosθsinθ)cosθsinθ
=(cosθsinθ)4(1+cosθsinθ3)cosθsinθ
=4(1+cosθsinθ)3
=4+4cosθsinθ3
=1+2.2cosθsinθ
=1+2sin20θ


1202288_1322401_ans_9a65e2019d344506b330fdb8b60ecc04.JPG

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