Question

Solve $\frac{\sin \theta }{1-\cot \theta }+\frac{\cos \theta }{1-\tan \theta }=$

Answer 1

$\frac{\sin \theta }{1-\cot \theta }+\frac{\cos \theta }{1-\tan \theta }$

$=\frac{{\sin }^2\theta }{\sin \theta -\cos \theta }+\frac{\cos \theta }{\cos \theta -\sin \theta }$

$=\frac{{\cos }^2\theta -{\sin }^2\theta }{\cos \theta -\sin \theta }$

$=\cos \theta +\sin \theta$