Question

Solve $\frac{x+1}{2}+\frac{y-1}{3}=8,$$\frac{x-1}{3}+\frac{y+1}{2}=9$

Answer 1

The pair of equations is,

$\frac{x+1}{2}+\frac{y-1}{3}=8$

$3\left(x+1\right)+2\left(y-1\right)=8\times 6$

$3x+3+2y-2=48$

$3x+2y+1=48$

$3x+2y=47$ (1)

$\frac{x-1}{3}+\frac{y+1}{2}=9$

$2\left(x-1\right)+3\left(y+1\right)=9\times 6$

$2x-2+3y+3=54$

$2x+3y+1=54$

$2x+3y=53$ (2)

From equation (1) and (2),

$x=7,y=13$