Question

Solve : $\frac{x^2-2x+3}{x^2-4x+3}>-3$

Answer 1

$\frac{x^2-2x+3}{x^2-4x+3}>-3$

$x^2-2x+3>-3(x^2-4x+3)$

$x^2-2x+3>-3x^2+12x-9$

$4x^2-14x+12>0$

$2x^2-7x+6>0$

$(x-2)(x-\frac{3}{2})>0$

$x>2,x>\frac{3}{2}$