MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Special Integrals - 1

Solve x+2x+...

Question

Solve $\frac{x + 2}{x + 1} + \frac{x + 1}{x + 2} = \frac{5}{2}$

Open in App

Solution

$\frac{x + 2}{x + 1} + \frac{x + 1}{x + 2} = \frac{5}{2} \Rightarrow \frac{{(x + 2)}^{2} + {(x + 1)}^{2}}{(x + 1) (x + 2)} = \frac{5}{2} \Rightarrow \frac{(x^{2} + 4 + 4 x) + (x^{2} + 2 x + 1)}{x^{2} + 3 x + 2} = \frac{5}{2} \Rightarrow 2 (2 x^{2} + 6 x + 5) = 5 (x^{2} + 3 x + 2) \Rightarrow 4 x^{2} + 12 x + 10 = 5 x^{2} + 15 x + 10 \Rightarrow x^{2} + 3 x = 0 \Rightarrow x (x + 3) = 0 x = 0, - 3.$

Suggest Corrections

thumbs-up

0

Similar questions

\frac{x - 1}{5} - \frac{x}{3} = 1 - \frac{x - 2}{2}

\sqrt{\frac{x}{x - 1}} + \sqrt{\frac{x - 1}{x}} = \frac{5}{2}

\frac{x + 1}{2} + \frac{2}{x + 1} = \frac{x + 1}{3} + \frac{3}{x + 1} - \frac{5}{6} (x \neq - 1)

x - \frac{1}{x} = 5

x^{2} + \frac{1}{x^{2}}

5 x - 2 (2 x - 3) = 2 (3 x - 1) + \frac{5}{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Special Integrals - 1

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Special Integrals - 1

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon