Question

Solve $\frac{x^2-(x+1)(x+2)}{5x+1}=6$

Answer 1

We have

$\frac{x^2-(x+1)(x+2)}{5x+1}=6$

$x^2-(x^2+3x+2)=6(5x+1)$

$x^2-x^2-3x-2=30x+6$

$-3x-2=30x+6$

$-3x-30x=6+2$

$-33x=8$

$x=\frac{-8}{33}$