Question

Solve:

$\frac{x+2y+1}{2x-y+1}=2;\frac{3x-y+1}{x-y+3}=5$

• A. $x=13,y=10$
• B. $x=17,y=5$
• C. $x=9,y=-5$
• D. None of these

Answer 1

The correct option is A $x=13,y=10$

$\Rightarrow \frac{x+2y+1}{2x-y+1}=2$
$\Rightarrow 4x-2y+2=x+2y+1$
$\Rightarrow 3x-4y=-\mathrm{1........}eq1$
$\Rightarrow \frac{3x-y+1}{x-y+3}=5$
$\Rightarrow 5x-5y+15=3x-y+1$
$\Rightarrow 2x-4y=-\mathrm{14........}eq2$
Substract eq1 and eq2
$\Rightarrow x=13$
put x=13 in eq1
$\Rightarrow 3\times 13-4y=-1$
$\Rightarrow -4y=-40\Rightarrow y=10$
Hence x=13 and y=10