Question

Solve $\frac{x+4}{3}+\frac{2x+3}{4}=7$

• A. $x=\frac{59}{20}$
• B. $x=\frac{59}{10}$
• C. $x=\frac{9}{10}$
• D. None of these

Answer 1

Answer: (B)

$x=\frac{59}{10}$

Given that:

$\frac{x+4}{3}+\frac{2x+3}{4}=7$

Taking LCM. We get,

$\frac{4\times (x+4)+3\times (2x+3)}{12}=7$

$\frac{4x+16+6x+9}{12}=7$

$\frac{10x+25}{12}=7$

$10x+25=84$

$10x=59$

$x=\frac{59}{10}$