Question

Solve $\frac{x-b-c}{a}+\frac{x-c-a}{b}+\frac{x-a-b}{c}=3$

Answer 1

$\frac{x-b-c}{a}+\frac{x-c-a}{b}+\frac{x-a-b}{c}=3$

put $x=a+b+c$

$\Rightarrow \frac{a+b+c-b-c}{a}+\frac{a+b+c-c-a}{b}+\frac{a+b+c-a-b}{c}=3$

$\Rightarrow \frac{a}{a}+\frac{b}{b}+\frac{c}{c}=3$.