Question

Solve $64x^2-625=0$, number of solutions are

Answer 1

We have $64x^2-625=0$

or $(8x{)}^2-(25{)}^2=0or(8x+25)(8x-25)=0$

i.e. 8x+25=0 or 8x-25=0 This gives x = $-\frac{25}{8}or\frac{25}{8}$

Thus $x=-\frac{25}{8},\frac{25}{8}$ are solutions of the given equation