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Question

Solve:
a2+5a+6a2a12×a4a24

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Solution

Given,

a2+5a+6a2a12×a4a24

=a2+3a+2a+6a24a+3a12×a4(a+2)(a2)

=a(a+3)+2(a+3)a(a4)+3(a3)×(a4)(a+2)(a2)

=(a+3)(a+2)(a4)(a+3)×(a4)(a+2)(a2)

=1a2.

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