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Byju's Answer
Standard XII
Mathematics
Cos(A+B)Cos(A-B)
Solve cos2θ...
Question
Solve
cos
2
θ
=
1
2
, then
θ
=
n
π
±
π
m
,
n
∈
I
. Find the value of
m
.
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Solution
cos
2
θ
=
1
2
⇒
cos
2
θ
(
1
√
2
)
2
⇒
cos
2
θ
=
cos
2
π
4
⇒
θ
=
n
π
±
π
4
,
n
∈
I
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0
Similar questions
Q.
Solve
cos
2
θ
=
1
2
, then
θ
=
n
π
±
π
2
,
n
∈
I
If true then enter
1
and if false then enter
0
Q.
Solving
sin
θ
=
√
3
2
then,
θ
=
n
π
+
(
−
1
)
n
π
m
,
n
∈
I
. Find
m
Q.
Solve
cos
3
x
+
sin
2
x
−
sin
4
x
=
0
, then
x
=
(
2
n
+
1
)
π
m
,
n
∈
I
or
n
π
+
(
−
1
)
n
π
m
,
n
∈
I
. Find the value of
m
.
Q.
Solution of
3
(
sec
2
θ
+
tan
2
θ
)
=
5
is
θ
=
n
π
±
π
m
. Find
m
.
Q.
The general solution of
4
tan
2
θ
=
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sec
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=
n
π
±
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m
. Then, find the value of
m
.
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Cos(A+B)Cos(A-B)
Standard XII Mathematics
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