Solve tan 3x-tan 2x1-tan 3xtan 2x-1

The correct option is A x=nπ+π4 Given, tan 3x tan 2x1+tan 3xtan 2x=1 #160; tan(3x 2x)=1 #160; tan x=1 #160; x=nπ+π4 . Where ...

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Standard XII

Mathematics

Special Integrals - 1

Solve tan 3...

Question

Solve $\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1$

x = n π + \frac{π}{4}

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x = n π + \frac{π}{5}

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x = n π + \frac{π}{3}

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Solution

The correct option is A $x = n π + \frac{π}{4}$
Given,

$\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1$

$tan (3 x - 2 x) = 1$

$tan x = 1$

$x = n π + \frac{π}{4}$ . Where $n$ is an integer.

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Similar questions

Q. Assertion :(A) :

\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x t a n 2 x} = 1 \Rightarrow x = n π + \frac{π}{4}, n \in l

Reason: (R) :

t a n x

is not defined at

x = n π + \frac{π}{2}, n \in l

Solve the equation: $\sqrt{(\frac{1}{16} + c o s^{4} x - \frac{1}{2} c o s^{2} x)} + \sqrt{(\frac{9}{16} + c o s^{4} x - \frac{3}{2} c o s^{2} x)} = \frac{1}{2}$

Q. The set of values of

x

for which

\frac{tan 3 x - tan 2 x}{1 + tan 3 x \cdot tan 2 x} = 1

is (where

n \in Z

)

Q. Assertion :

\frac{tan 3 x - tan 2 x}{1 + tan 2 x tan 3 x} = 1

, then

x = n π + \frac{π}{4}, \forall n \in I

Reason:

tan x

is not defined at

x = n π + \frac{π}{2}, n \in I

Q. Assertion :General solution of equation

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1 i s x = n π + \frac{π}{4}

Reason:

tan x

is not defined at odd multiple of

\frac{π}{2}

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Solve tan3x−tan2x1+tan3xtan2x=1

The correct option is A x=nπ+π4Given,tan3x−tan2x1+tan3xtan2x=1 tan(3x−2x)=1 tanx=1 x=nπ+π4. Where n is an integer.

Solve $\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1$

The correct option is A $x = n π + \frac{π}{4}$
Given,

$\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1$

$tan (3 x - 2 x) = 1$

$tan x = 1$

$x = n π + \frac{π}{4}$ . Where $n$ is an integer.