Question

Solve
$\frac{12x^2+18x+12}{18x^2+12x+58}=\frac{2x+3}{3x+2}$

solution is $-\frac{15}{8}$

If true then enter $1$ and if false then enter $0$

Answer 1

$\frac{12x^2+18x+12}{18x^2+12x+58}=\frac{2x+3}{3x+2},$

$\frac{6x^2+9x+6}{9x^2+6x+29}=\frac{2x+3}{3x+2}$

$(6x^2+9x+6)(3x+2)=(2x+3)(9x^2+6x+29)$

$18x^3+39x^2+36x+12=18x^3+39x^2+76x+87$

$36x+12=76x+87$

$40x=-75$

$x=-\frac{15}{8}$