Question

Solve : $\frac{2}{x}+\frac{2}{3y}=\frac{1}{6}$ and $\frac{3}{x}+\frac{2}{y}=0$.

Hence, find ${}^{\prime }{m}^{\prime }$ for which $y=mx-4$.

• A. $x=3;y=-5$ and $m=2$
• B. $x=6;y=-4$ and $m=0$
• C. $x=2;y=-3$ and $m=0$
• D. $x=4;y=-4$ and $m=2$

Answer 1

The correct option is B $x=6;y=-4$ and $m=0$

$\frac{2}{x}+\frac{2}{3y}=\frac{1}{6};\frac{2}{y}+\frac{3}{x}=0$

Multiplying the 2nd equation by -1/3 and Adding:

$\frac{1}{x}=\frac{1}{6};y=-4x=6y=mx-4Hencem=0$