Question

Solve: $\frac{2x+3}{5x}-\frac{7}{x}+4=\frac{2}{3x};x\ne 0$

• A. $1\frac{14}{33}$
• B. $1\frac{20}{33}$
• C. $1\frac{23}{33}$
• D. $1\frac{19}{33}$

Answer 1

The correct option is B $1\frac{20}{33}$

$\frac{2x+3}{5x}-\frac{7}{x}+4=\frac{2}{3x}$

$\Rightarrow \frac{2x+3}{5x}-\frac{7}{x}-\frac{2}{3x}=-4$

$\Rightarrow \frac{6x+9-105-10}{15x}=-4$

$\Rightarrow 6x-106=-60x$

$\Rightarrow 6x+60x=106$

$\Rightarrow x=\frac{106}{66}=\frac{53}{33}=1\frac{20}{33}$