Solve 2x - 5-10 - x-5 - x-1 - x

The correct option is A 1 2x+5 / 10 = x / 5 x / 1 x 2x+5 / 10 = x(1 x) 5x / 5(1 x) (1 x)(2x+5) = 2(x(1 x) ...

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Byju's Answer

Standard IX

Mathematics

Every Point on the Bisector of an Angle Is Equidistant from the Sides of the Angle.

Solve 2x + ...

Question

Solve $\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x}$

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Solution

The correct option is A $- 1$
$\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x} \frac{2 x + 5}{10} = \frac{x (1 - x) - 5 x}{5 (1 - x)} (1 - x) (2 x + 5) = 2 (x (1 - x) - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 (x - x^{2} - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 x - 2 x^{2} - 10 x + 5 = - 5 x x = - 1$

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Solve 2x+510=x5−x1−x

The correct option is A −12x+510=x5−x1−x2x+510=x(1−x)−5x5(1−x)(1−x)(2x+5)=2(x(1−x)−5x)2x−2x2+5−5x=2(x−x2−5x)2x−2x2+5−5x=2x−2x2−10x+5=−5xx=−1

Solve $\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x}$

The correct option is A $- 1$
$\frac{2 x + 5}{10} = \frac{x}{5} - \frac{x}{1 - x} \frac{2 x + 5}{10} = \frac{x (1 - x) - 5 x}{5 (1 - x)} (1 - x) (2 x + 5) = 2 (x (1 - x) - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 (x - x^{2} - 5 x) 2 x - 2 x^{2} + 5 - 5 x = 2 x - 2 x^{2} - 10 x + 5 = - 5 x x = - 1$