Solve 2x-x-3-1-2x-3-3x-9- x-3 2x-3 -0 and find the value of x-1

Obviously the given equation is valid if nbsp; x 3≠ 0 and 2x+3≠ 0 Multiplying throughout by (x 3)(2x + 3) we get 2x(2x + 3) + 1(x 3) + 3x + 9 = 0or ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation by Common Factors

Solve 2x/x-...

Question

Solve $\frac{2 x}{x - 3} + \frac{1}{2 x + 3} + \frac{3 x + 9}{(x - 3) (2 x + 3)} = 0$ and find the value of $x + 1$

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Solution

Obviously the given equation is valid if $x - 3 \neq 0 a n d 2 x + 3 \neq 0$
Multiplying throughout by (x - 3)(2x + 3) we get 2x(2x + 3) + 1(x - 3) + 3x + 9 = 0
or $4 x^{2} + 10 x + 6 = 0$
or $2 x^{2} + 5 x + 3 = 0$
or (2x + 3)(x + 1) = 0
But $2 x + 3 \neq 0$ so we get x + 1 = 0
This gives x = -1 as the only solution of the given equation

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The value of

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Solve 2xx−3+12x+3+3x+9(x−3)(2x+3)=0 and find the value of x+1

Obviously the given equation is valid if x−3≠0and2x+3≠0Multiplying throughout by (x - 3)(2x + 3) we get 2x(2x + 3) + 1(x - 3) + 3x + 9 = 0or 4x2+10x+6=0or 2x2+5x+3=0or (2x + 3)(x + 1) = 0But 2x+3≠0 so we get x + 1 = 0This gives x = -1 as the only solution of the given equation

Solve $\frac{2 x}{x - 3} + \frac{1}{2 x + 3} + \frac{3 x + 9}{(x - 3) (2 x + 3)} = 0$ and find the value of $x + 1$