Solve- 2x-x - 4 - 2x - 5-x - 3 - 25-3

The correct option is C x= 6, x=40/13 2x(x 3)+(2x 5)(x 4)(x 4)(x 3)=253 2x^2 6x+2x^2 8x 5x+20x^2 7x+12=253 4x^2 19x+20x^2 7x+12=253 12 ...

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Byju's Answer

Standard IX

Mathematics

Product Law

Solve: 2x/x...

Question

Solve: $\frac{2 x}{x - 4} + \frac{2 x - 5}{x - 3} = \frac{25}{3}$

x = 3, x = \frac{90}{19}

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x = 9, x = \frac{70}{23}

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x = 6, x = \frac{40}{13}

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Solution

The correct option is C $x = 6, x = \frac{40}{13}$
$\frac{2 x (x - 3) + (2 x - 5) (x - 4)}{(x - 4) (x - 3)} = \frac{25}{3}$
$\frac{2 x^{2} - 6 x + 2 x^{2} - 8 x - 5 x + 20}{x^{2} - 7 x + 12} = \frac{25}{3}$
$\frac{4 x^{2} - 19 x + 20}{x^{2} - 7 x + 12} = \frac{25}{3}$
$12 x^{2} - 57 x + 60 = 25 x^{2} - 175 x + 300$
$13 x^{2} - 118 x + 240 = 0$
Hence, $(13 x - 40) (x - 6) = 0$

$x = \frac{40}{13}$ or $x = 6$

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Similar questions

Q. Solve the following quadratic equation by factorization, the roots are :

6

\frac{40}{13}

\frac{2 x}{x - 4} + \frac{2 x - 5}{x - 3} = \frac{25}{3}

Q. Solve for

^{'} x^{'} : \frac{2 x}{x - 4} + \frac{2 x - 5}{x - 3} = \frac{25}{3}, x \neq 4, 3

Q. Solve:

x + 6 - 3 x - 5 - 2 (x - 5) = 2 x - 9 - 2 x + 5 - 3 (x + 1)

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve the following linear equations.

2 (3 - 2 x) = 13

\frac{x}{2} = 5 + \frac{x}{3}

7 (x - 2) = 2 (2 x - 4)

3 x - \frac{1}{3} = 2 (x - \frac{1}{2}) + 5

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Solve: 2xx−4+2x−5x−3=253

The correct option is C x=6,x=40132x(x−3)+(2x−5)(x−4)(x−4)(x−3)=2532x2−6x+2x2−8x−5x+20x2−7x+12=2534x2−19x+20x2−7x+12=25312x2−57x+60=25x2−175x+30013x2−118x+240=0Hence, (13x−40)(x−6)=0x=4013 or x=6

Solve: $\frac{2 x}{x - 4} + \frac{2 x - 5}{x - 3} = \frac{25}{3}$