Question

Solve: $\frac{3x-1}{2}<-3$ and $\frac{3x+8}{5}+11<0$

Answer 1

$\frac{3x-1}{2}<-3⟹3x-1<-6⟹3x<-5⟹x<-\frac{5}{3}$

$\frac{3x+8}{5}<-11⟹3x+8<-55⟹3x<-63⟹x<-21$

The intersection of $x<-\frac{5}{3}$ and $x<-21$ is the solution for the problem.

Hence, the solution is $x<-21$.