Question

Solve $\frac{3x-10}{2}\ge \frac{x+1}{6}-1$, where $x$ is a ntaural no. less than 10.

Answer 1

We have $\frac{3x-10}{2}\ge \frac{x+1}{6}-1$
or $\frac{3x-10}{3}\ge \frac{x-5}{6}$
or $6x-20\ge x-5$
or $5x\ge 15$
or $x\ge 3$
so the natural no. les than 10 are $3,4,5,6,7,8,9$.