Question

Solve $\frac{3x-4}{2}\ge \frac{x+1}{4}-1$

• A. $x\le 1$
• B. $x>1$
• C. $x\ge 1$
• D. $x<2$

Answer 1

Answer: (C)

$x\ge 1$

$\frac{3x-4}{2}\ge \frac{x+1}{4}-1$
$=>\frac{3x-4}{2}\ge \frac{x+1-4}{4}$
$=>3x-4\ge \frac{x-3}{2}$
$=>6x-8\ge x-3$
$5x\ge 5$
$x\ge 1$