Solve - 7x-1-4 - 14-3 - 1-3- 7x - 1-x-2- - 5x-3

The correct option is A x= 5 Given, 7x 1 4 + 14 3 = 1 3 [ 7x 1 x 2 #160;] 5x 3 Multiplying both sides by 12(LCM of 4, 3, 3, 2 and 3), we ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Performing Mathematical Operations on Equation

Solve : 7x-...

Question

Solve : $\frac{7 x - 1}{4} + \frac{14}{3} = \frac{1}{3} [7 x - \frac{1 - x}{2}] - \frac{5 x}{3}$

x = - 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x = - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = 7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x = - 5$
Given, $\frac{7 x - 1}{4} + \frac{14}{3} = \frac{1}{3} [7 x - \frac{1 - x}{2}] - \frac{5 x}{3}$
Multiplying both sides by 12(LCM of 4, 3, 3, 2 and 3), we get
$3 (7 x - 1) + 4 \times 14 = 4 [7 x - \frac{1 - x}{2}] - 4 \times 5 x o r, 21 x - 3 + 56 = 28 x - 2 (1 - x) - 20 x o r, 21 x + 53 = 8 x - 2 + 2 x o r, 21 x + 53 = 10 x - 2$
Transposing the terms,we get
$21 x - 10 x = - 2 - 53 o r, 11 x = - 55 ⟹ x = - 5$
Thus, the solution of the equation is x = -5.

Suggest Corrections

Similar questions

Q. Solve for

x

\frac{2 - 7 x}{1 - 5 x} = \frac{3 + 7 x}{4 + 5 x}

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve the following equations:

\sqrt{2 x^{2} + 5 x - 7} + \sqrt{3 (x^{2} - 7 x + 6)} - \sqrt{7 x^{2} - 6 x - 1} = 0

Q. Solve

\frac{4 x}{3} - \frac{9}{4} < x + \frac{3}{4}, \frac{7 x - 1}{3} - \frac{7 x + 2}{6} > x

Q. Solve for

x

\frac{x - 1}{7 x - 14} =

\frac{x - 3}{7 x - 26}

Join BYJU'S Learning Program

Solve : 7x−14+143=13[7x−1−x2]−5x3

Solve : $\frac{7 x - 1}{4} + \frac{14}{3} = \frac{1}{3} [7 x - \frac{1 - x}{2}] - \frac{5 x}{3}$