Question

Solve
${\int }_0^{10\pi }(|\sin x|+|\cos x|)dx$

Answer 1

Given,

${\int }_0^{10\pi }(|\sin x|+|\cos x|)dx$

$={\int }_0^{10\pi }|\sin x|dx+{\int }_0^{10\pi }|\cos x|dx$

$=[\cos x{]}_0^{10\pi }+[\sin x{]}_0^{10\pi }$

$=0+0=0$