Question

Solve ${\int }_0^2(3x^2-2x+5)dx$

Answer 1

$\underset{0}{\overset{2}{\int }}\left(3x^2-2x+5\right)dx$

$={\left(\frac{3x^3}{3}-\frac{2x^2}{2}+5x\right)}_0^2$

$={\left(x^3-x^2+5x\right)}_0^2$

$=\left(8-4+10\right)-\left(0\right)$

$=14$