Question

Solve ${\int }_0^2$ ($x^2$ +$1$) dx

• A. $\frac{2}{3}$
• B. $\frac{14}{3}$
• C. $\frac{8}{3}$
• D. $\frac{11}{3}$

Answer 1

Answer: (B)

$\frac{14}{3}$

${\int }_0^2(x^2+1)dx={\int }_0^2{x}^{2}dx+{\int }_0^{2}1dx={\left[\frac{x^3}{3}\right]}_0^2+{\left[x\right]}_0^2=\frac{8}{3}-0+2-0=\frac{14}{3}$