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Question

Solvea0xa2+x2dx

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Solution

Ia0xa2+x2dxPut t=a2+x2dtdx=2xdt2=xdx,I=dt2tI=12.t12+112+1+CI=12.t12+CI=t+CI=[x2+a2]a0I=a2aI=a(21)

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