wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve:
π20sinϕcos5 ϕ dϕ

Open in App
Solution

I=π/20sinϕcos5ϕdϕ.

Let sinϕ=t. Then, cosϕdϕ=dt

Also, ϕ=0t=sin0=0 and ϕ=π2t=sinπ2=1

I=10t(1t2)2dt=10t(12t2+t4)dt

I=[23t3/247t7/2+211t11/2]10=2347+211=64231


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon