Question

Solve $\int \frac{1}{{\log }_{x}e}dx$

Answer 1

Let,

$=\int 1.{\log }_{e}xdx$

Integrating by parts taking $lo{g}_{e}x$ as first function

$={\log }_{e}x\times x-\int \frac{1}{x}\times xdx$
$=x{\log }_{e}x-x+c$