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Question

Solve:
2cosxdx(1sinx)(2cos2x)

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Solution

2cosxdx(1sinx)(2cos2x)2cosxdx(1sinx)(1+sin2x)sinx=t,dtdx=cosx2dx(1t)(2t2)=2[12dt1t+12t+1t2+1dt]=dt1t+12t+1t2+1dtlog|t1|+tan1t+12log(t2+1)+C=tan1t+log(t2+1|t1|)+Ct=sinx

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