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Question

Solve :-
cos2x(sinx+cosx)2dx

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Solution

Now,
cos2x(sinx+cosx)2dx
=cos2xsin2x+cos2x+2sinx.cosxdx
=cos2x1+sin2xdx
=12d(1+sin2x)1+sin2x
=12log|(1+sin2x)|+c. [ Where c is integrating constant]

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