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Question

Solve: cos3xsinxdx.

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Solution

Now,
cos3xsinxdx
=(1sin2x).cosxsinxdx
Let sinx=z or, cosx dx=dz.
Using these in above expression we get,
=(1z2)dzz
=1zdzz32dz
=2z25z52+c [ Where c is constant]
=2sinx25(sinx)52+c

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