wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Solve cosxsinx1+sin2xdx

Open in App
Solution

Solve the given trigonometric function.

=cosxsinx1+sin2xdx

=cosxsinxsin2x+cos2x+2sinxcosxdx

=cosxsinx(cosx+sinx)2dx

Let cosx+sinx=t

Then,

ddx(cosx+sinx)=ddxt

sinx+cosx=dtdx

(cosxsinx)dx=dt

Now,

dtt2

=t2dt

=t2+12+1

=1t=1cosx+sinx

Hence, this is the answer.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Trigonometric Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon