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Byju's Answer
Standard IX
Mathematics
Use of Trigonometric Table
Solve ∫ dx ...
Question
Solve
∫
d
x
sin
x
+
√
3
cos
x
A
1
2
log
∣
∣
∣
tan
(
x
2
−
π
6
)
∣
∣
∣
+
c
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B
1
2
log
∣
∣
∣
tan
(
x
4
−
π
6
)
∣
∣
∣
+
c
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C
1
2
log
∣
∣
∣
tan
(
x
2
+
π
6
)
∣
∣
∣
+
c
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D
1
2
log
∣
∣
∣
tan
(
x
4
+
π
3
)
∣
∣
∣
+
c
where
c
is an arbitrary constant
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Solution
The correct option is
D
1
2
log
∣
∣
∣
tan
(
x
2
+
π
6
)
∣
∣
∣
+
c
Let
I
=
∫
d
x
sin
x
+
√
3
cos
x
=
∫
d
x
2
sin
(
x
+
π
3
)
=
1
2
∫
csc
(
x
+
π
3
)
d
x
=
1
2
log
tan
(
x
2
+
π
6
)
+
c
Suggest Corrections
0
Similar questions
Q.
I
:
∫
1
3
+
4
cos
x
d
x
=
1
√
7
l
o
g
[
√
7
+
tan
(
x
/
2
)
√
7
−
tan
(
x
/
2
)
]
+
c
I
I
:
∫
d
x
cos
x
−
sin
x
=
1
√
2
log
|
tan
(
x
2
−
3
π
8
)
|
+
c
Q.
If,
I
=
∫
d
x
s
i
n
(
x
−
π
3
)
c
o
s
x
then I equals
Q.
∫
1
0
s
i
n
−
1
(
2
x
1
+
x
2
)
d
x
=
Q.
∫
1
0
s
i
n
−
1
(
2
x
1
+
x
2
)
d
x
=
[Karnataka CET 1999]