CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve dxsinx+3cosx

A
12logtan(x2π6)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12logtan(x4π6)+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12logtan(x2+π6)+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12logtan(x4+π3)+c
where c is an arbitrary constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 12logtan(x2+π6)+c
Let I=dxsinx+3cosx
=dx2sin(x+π3)
=12csc(x+π3)dx
=12logtan(x2+π6)+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Adaptive Q10
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon