Solve $\int \frac{e^{x} + 1}{e^{x} + x} d x$

log (e^{x} + 1) + C

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log (e^{x} + x) + C

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log (e^{x} + 2) + C

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None of these

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Solution

The correct option is C $log (e^{x} + x) + C$

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