We have,
I=∫(4x3+5x4)(x5+x4+6)2dx
Let t=x5+x4+6
dt=(5x4+4x3)dx
Therefore,
I=∫1(t)2dt
I=−1t+C
On putting the value of t, we get
I=−1(x5+x4+6)+C
Hence, this is the answer.
The degree of the polynomial obtained when 8−6x+x2−7x3+x5 is subtracted from x4−6x3+x2−3x+1 is: