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Question

Solve: log(1+x)1+xdx

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Solution

log(1+x)1+xdx
Put log(1+x)=t
Differentiating 11+xdx=dt
tdt
=[t22]+c
=(log(1+x)]22+c.

1229471_1301510_ans_bb752701a9a94f73919aab34ed2dca17.jpg

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