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Question

Solve : log(tanx2)sinxdx

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Solution

=log(tanx2)sinxdx
log(tanx2)=t
differentiating
⎢ ⎢ ⎢1tanx2⎥ ⎥ ⎥×sec2x2×12dx=dt⎜ ⎜cosx2sinx2⎟ ⎟×12×(cos2x2)dx=dt1sinxdx=dt
I=log(tanx2)sinxdx=tdtt22+c
I=12[log(tanx2)]2+c

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