Consider the given function
∫sec2xcosec2xdx
=∫1cos2x1sin2xdx
=∫sin2xcos2xdx
=∫tan2xdx
=∫(sec2x−1)dx
=∫sec2xdx−∫1dx
=tanx−x+C
Hence, this is the aanswer.
Find the following integrals. ∫sec2xcosec2xdx.