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Question

Solve:
sin(xα)sin(x+α)dx

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Solution

sin(xα)sin(xα)dx=sin[(x+α)2α]sin(x+α)dx
=[sin(x+α)cos2αcos(x+α.sin2α]sin(x+α)dx
=[cos2αcot(x+α)sin2α]dx
=cos2αdxsin2αcot(x+α)dx
=xcos2αsin2α.log|(sin(x+α)|+C

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