Question

Solve$\int \frac{\sin x}{1+\cos x}dx$

Answer 1

$\int \frac{\sin x}{1+\cos x}dx$

Put, $1+\cos x=t$

$⟹-\sin xdx=dt$

Now, $\int \frac{\sin x}{1+\cos x}dx=\int \frac{-1}{t}dt$

$=-\log t+c$

$=-\log (1+\cos x)+c$