Special Integrals -
Solve : ∫sinxsin3xdx
⇒∫sinx3sinx−4sin3xdx
⇒∫dx3−4sin2x sin3θ=3sinθ−4sin3θ
⇒∫dx3−41−cos2x2
⇒∫dx3−2(1−cos2x)
⇒∫dx3−2+2cos2x cos2θ=1−tan2θ1+tan2θ
⇒∫dx1+2cos2x
⇒∫dx1+2(1+t2)1+t2 (where t=tanxdt=sec2xdxdx=dt1+t2)
⇒∫dt1+t2+2−2t2
⇒dt3−t2
⇒∫12.√3ln(|√3+tanx√3−tanx|)+c
using ∫1x2−a2=12aln|a−xa+x|
![1060612_1176902_ans_6c6672ba629a44e5a037a401eb58e9ae.png](https://search-static.byjusweb.com/question-images/toppr_ext/questions/1060612_1176902_ans_6c6672ba629a44e5a037a401eb58e9ae.png)