Question

Solve $\int \frac{x^2}{x+1}dx$.

Answer 1

We have,

$I=\int \frac{x^2}{x+1}dx$

$I=\int \frac{x^2-1+1}{x+1}dx$

$I=\int (x-1+\frac{1}{x+1})dx$

$I=\frac{x^2}{2}-x+\log (x+1)+C$

Hence, this is the answer.